If a three-phase circuit has 240 V, using 100 A with a power factor of 0.5, what is the real power?

If a three-phase circuit has 240 V, using 100 A with a power factor of 0.5, what is the real power?

• A. 0.24 W
• B. 12,000 W
• C. 20,760 W
• D. 24,000 kW

Answer: (C)

To determine the real power in a three-phase circuit, the formula commonly used is: \[ P = \sqrt{3} \times V \times I \times \text{power factor} \] Where: - \( P \) is the real power in watts (W), - \( V \) is the voltage (in volts), - \( I \) is the current (in amperes), - the power factor accounts for the phase difference between voltage and current. In this scenario, the voltage is 240 V, the current is 100 A, and the power factor is 0.5. Using these values, the calculation proceeds as follows: 1. First, calculate the product of voltage and current: \[ V \times I = 240 \, \text{V} \times 100 \, \text{A} = 24,000 \, \text{VA} \] 2. Now, multiply this by the square root of 3 (approximately 1.732): \[ \sqrt{3} \times (240 \times 100) = \sqrt{3} \times 24,000 \] 3. Finally, calculate the real power using the power

To determine the real power in a three-phase circuit, the formula commonly used is:

[ P = \sqrt{3} \times V \times I \times \text{power factor} ]

Where:

• ( P ) is the real power in watts (W),

• ( V ) is the voltage (in volts),

• ( I ) is the current (in amperes),

• the power factor accounts for the phase difference between voltage and current.

In this scenario, the voltage is 240 V, the current is 100 A, and the power factor is 0.5. Using these values, the calculation proceeds as follows:

1. First, calculate the product of voltage and current:

[ V \times I = 240 , \text{V} \times 100 , \text{A} = 24,000 , \text{VA} ]

2. Now, multiply this by the square root of 3 (approximately 1.732):

[ \sqrt{3} \times (240 \times 100) = \sqrt{3} \times 24,000 ]

3. Finally, calculate the real power using the power